3x^2=3000

Solution for 3x^2=3000 equation:

3x^2=3000

We move all terms to the left:

3x^2-(3000)=0

a = 3; b = 0; c = -3000;
Δ = b2-4ac
Δ = 02-4·3·(-3000)
Δ = 36000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{36000}=\sqrt{3600*10}=\sqrt{3600}*\sqrt{10}=60\sqrt{10}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-60\sqrt{10}}{2*3}=\frac{0-60\sqrt{10}}{6}
=-\frac{60\sqrt{10}}{6}
=-10\sqrt{10}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+60\sqrt{10}}{2*3}=\frac{0+60\sqrt{10}}{6}
=\frac{60\sqrt{10}}{6}
=10\sqrt{10}
$